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Electrical · in the TradeTools app

Voltage Drop Calculator

AC voltage drop on a branch circuit or feeder from the Table 9 conductor impedance, the voltage left at the load, and the minimum conductor size that keeps the drop within the recommended 3 %.

NEC Ch. 9 Table 9
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Voltage Drop result: 3.49 % on 200 feet of 10 AWG copper at 20 A

Worked example

200 ft to the shop on 10 AWG at 20 A — how much do you lose?

Inputs
Voltage / phase240 V, single-phase
Conductor10 AWG copper
RacewayPVC
One-way length200 ft
Load20 A
Power factor0.85
What the app shows
Voltage drop8.37 V
Percent3.49 % — above the recommended 3 %
Voltage at the load231.6 V
Effective impedance1.046 Ω/kft (NEC Ch. 9 Table 9)
Smallest size within 3 %8 AWG

Impedance is computed from Table 9's resistance and reactance for uncoated copper in PVC at 0.85 power factor: 1.2 × 0.85 + 0.050 × 0.527 = 1.046 Ω per 1000 ft. Two conductors, 200 ft, 20 A: 2 × 200 × 20 × 1.046 / 1000 = 8.37 V, or 3.49 % of 240 V. 8 AWG brings it under 3 %.

How it's calculated

The table behind the number

The app takes the conductor's AC resistance and inductive reactance from NEC Chapter 9 Table 9 for the raceway material, combines them at the power factor you enter (R·cos θ + X·sin θ, Table 9 Note 2), and computes the drop for single-phase (2 × length) or three-phase (√3 × length) circuits. It reports the drop in volts and percent, the voltage at the load, and the smallest conductor that stays under the 3 % that 210.19(A) and 215.2(A) recommend in their informational notes.

  • NEC 2023 Chapter 9, Table 9AC resistance and reactance for 600 V conductors, by raceway material
  • NEC 2023 210.19(A) Informational Note No. 43 % branch-circuit drop — a recommendation, not a requirement (90.5(C))
  • NEC 2023 215.2(A) Informational Note No. 25 % combined feeder and branch-circuit drop — recommendation

Questions

Before you trust the number

Is 3 % voltage drop a code requirement?

No. The 3 % and 5 % figures live in informational notes, which 90.5(C) defines as explanatory material. Your AHJ or the job specification may make them mandatory; the NEC itself does not.

Why does the printed 0.85 PF column give a different answer?

Table 9 also prints an 'effective Z at 0.85 PF' column rounded to two digits; the app computes the impedance from the R and X columns for the power factor you enter, which is what the table's Note 2 describes. The conclusion — over 3 %, 8 AWG gets under — is the same.